1.5x^2-24x+18=0

Solution for 1.5x^2-24x+18=0 equation:

1.5x^2-24x+18=0

a = 1.5; b = -24; c = +18;
Δ = b2-4ac
Δ = -242-4·1.5·18
Δ = 468
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{468}=\sqrt{36*13}=\sqrt{36}*\sqrt{13}=6\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-6\sqrt{13}}{2*1.5}=\frac{24-6\sqrt{13}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+6\sqrt{13}}{2*1.5}=\frac{24+6\sqrt{13}}{3}
$